How do you find the zeroes for $f\left(x\right)={x}^{2}-9x-70$ ?

Anderson Melton
2022-01-23
Answered

How do you find the zeroes for $f\left(x\right)={x}^{2}-9x-70$ ?

You can still ask an expert for help

Bottisiooq

Answered 2022-01-24
Author has **9** answers

Step 1

We need to think of two numbers, that, when I add them, sum up to -9, and when I multiply them, have a product of -70. Since the product is negative, we know the signs must be different.

Through some thought, we arrive at -14 and 5 as our two numbers, because

$-14+5=-9$ and

$-14\times 5=-70$

Thus, our equation is as follows:

$(x-14)(x+5)=0$

To find the zeroes, we take the opposite signs to get

$x=14$ and $x=-5$

We need to think of two numbers, that, when I add them, sum up to -9, and when I multiply them, have a product of -70. Since the product is negative, we know the signs must be different.

Through some thought, we arrive at -14 and 5 as our two numbers, because

Thus, our equation is as follows:

To find the zeroes, we take the opposite signs to get

Nevaeh Jensen

Answered 2022-01-25
Author has **14** answers

Step 1

$f\left(x\right)={x}^{2}-9x-70=0$

To solve f(x), find 2 numbers (real roots) knowing the sum$(-b=9)$ and the product $(c=-70)$ . They are: - 5 and 14.

Note . This method avoids proceeding the lengthy factoring by grouping and solving the 2 binomials.

To solve f(x), find 2 numbers (real roots) knowing the sum

Note . This method avoids proceeding the lengthy factoring by grouping and solving the 2 binomials.

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