How do you solve x^{2}+4x-21=0?

David Rojas

David Rojas

Answered question

2022-01-21

How do you solve x2+4x21=0?

Answer & Explanation

Johnny Cummings

Johnny Cummings

Beginner2022-01-22Added 7 answers

Step 1
We are going to solve it with Δ
The equation is of the form ax2+bx+c=0
a=1, b=4, c=21
Δ=b24ac
Δ=424×1×(21)
Δ=16+84
Δ=100=(10)
x1=bΔ2a
x1=4102
x1=142
x1=7
x2=b+Δ2a
x2=4+102
x2=62
x2=3
Jordyn Horne

Jordyn Horne

Beginner2022-01-23Added 16 answers

Step 1
You can solve this by using the general formula for complete quadratic equations.
x=b±b24ac2a
For a complete quadratic equation
ax2+bx+c=0
Lets

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