# How do you find the solution to the quadratic equation

How do you find the solution to the quadratic equation $0={x}^{2}+5x+6$?
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Serifluinueyk
Step 1
${x}^{2}+5x+6=0$
${x}^{2}+2x+3x+6=0$
$x×\left(x+2\right)+3\left(x+2\right)=0$
$\left(x+2\right)×\left(x+2\right)=0$
$x=-2$ or -3
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euromillionsna
RizerMix
Step 1 Are there any two numbers that sum to the middle term (5), and have a product of the last term (6)? After some trial and error, we arrive at 2 and 3. Thus, we can factor the right side of our quadratic as $0=\left(x+2\right)\left(x+3\right)$ Setting both of our factors equal to zero, we get $x=-2$ and $x=-3$