Dayton Burnett
2022-01-20
Answered

How do you find the solution to the quadratic equation $0={x}^{2}+5x+6$ ?

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Serifluinueyk

Answered 2022-01-21
Author has **7** answers

Step 1

${x}^{2}+5x+6=0$

${x}^{2}+2x+3x+6=0$

$x\times (x+2)+3(x+2)=0$

$(x+2)\times (x+2)=0$

$x=-2$ or -3

euromillionsna

Answered 2022-01-22
Author has **16** answers

Step 1

Lets

Lets

RizerMix

Answered 2022-01-27
Author has **438** answers

Step 1
Are there any two numbers that sum to the middle term (5), and have a product of the last term (6)?
After some trial and error, we arrive at
2 and 3. Thus, we can factor the right side of our quadratic as
$0=(x+2)(x+3)$
Setting both of our factors equal to zero, we get
$x=-2$ and $x=-3$

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If I would draw a right triangle with legs of length 1 centimeter with a ruler then its hypotenuse should be equal to $\sqrt{2}$ which is an irrational number - therefore its decimal representation, which is the limit of the sequence $\underset{n\to \mathrm{\infty}}{lim}\sum _{i=0}^{\mathrm{\infty}}\frac{{a}_{i}}{{10}^{i}}$, has infinitely many numbers after the interger part of$\sqrt{2}$.

What exactly can the ruler measure when drawing such a triangle, considering the fact that we draw irrational number (which by definition is infinitely long)?

What exactly can the ruler measure when drawing such a triangle, considering the fact that we draw irrational number (which by definition is infinitely long)?

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Use factor formula to show that

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A.

B.

C.

D.

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