How do you factor and solve

$2{x}^{2}-3=125$ ?

Ella Bradshaw
2022-01-23
Answered

How do you factor and solve

$2{x}^{2}-3=125$ ?

You can still ask an expert for help

Amina Hall

Answered 2022-01-24
Author has **11** answers

Step 1

$2{x}^{2}-3=125$

Subtract 125 on both sides

$2{x}^{2}-128=0$

Divide both sides by 2

${x}^{2}-64=0$

Using

${a}^{2}-{b}^{2}=(a+b)(a-b)$

${x}^{2}-64=(x+8)(x-8)$

So

$(x+8)(x-8)=0$

$x=\pm 8$

Subtract 125 on both sides

Divide both sides by 2

Using

So

hmotans

Answered 2022-01-25
Author has **8** answers

Step 1
Move all the terms to one side of the equation
$2{x}^{2}-3=125$
$2{x}^{2}-3-125=\text{\u29f8}125-\text{\u29f8}125$
$2{x}^{2}-128=0$
Now take out a factor of 2
$(2\times {x}^{2})-(2\times 64)=0$
$2({x}^{2}-64)=0$
We now have a term in the parentheses that looks like
$({a}^{2}-{b}^{2})$
This is called a difference of squares
We can factor a difference of squares like this:
$({a}^{2}-{b}^{2})=(a-b)(a+b)$
Lets

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