How do you factor and solve 2x^{2}-3=125?

Question

How do you factor and solve 2x^{2}-3=125?

Ella Bradshaw 2022-01-23 Answered

How do you factor and solve

2 x^{2} - 3 = 125

?

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Expert Answer

Amina Hall

Answered 2022-01-24 Author has 11 answers

Step 1

2 x^{2} - 3 = 125

Subtract 125 on both sides

2 x^{2} - 128 = 0

Divide both sides by 2

x^{2} - 64 = 0

Using

a^{2} - b^{2} = (a + b) (a - b)

x^{2} - 64 = (x + 8) (x - 8)

So

(x + 8) (x - 8) = 0

x = \pm 8

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hmotans

Answered 2022-01-25 Author has 8 answers

Step 1 Move all the terms to one side of the equation

2 x^{2} - 3 = 125

2 x^{2} - 3 - 125 = ⧸ 125 - ⧸ 125

2 x^{2} - 128 = 0

Now take out a factor of 2

(2 \times x^{2}) - (2 \times 64) = 0

2 (x^{2} - 64) = 0

We now have a term in the parentheses that looks like

(a^{2} - b^{2})

This is called a difference of squares We can factor a difference of squares like this:

(a^{2} - b^{2}) = (a - b) (a + b)

Lets

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How do you factor and solve 2x^{2}-3=125?

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