# How do you factor and solve 2x^{2}-3=125?

How do you factor and solve
$2{x}^{2}-3=125$?
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Amina Hall
Step 1
$2{x}^{2}-3=125$
Subtract 125 on both sides
$2{x}^{2}-128=0$
Divide both sides by 2
${x}^{2}-64=0$
Using
${a}^{2}-{b}^{2}=\left(a+b\right)\left(a-b\right)$
${x}^{2}-64=\left(x+8\right)\left(x-8\right)$
So
$\left(x+8\right)\left(x-8\right)=0$
$x=±8$
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hmotans
Step 1 Move all the terms to one side of the equation $2{x}^{2}-3=125$ $2{x}^{2}-3-125=\text{⧸}125-\text{⧸}125$ $2{x}^{2}-128=0$ Now take out a factor of 2 $\left(2×{x}^{2}\right)-\left(2×64\right)=0$ $2\left({x}^{2}-64\right)=0$ We now have a term in the parentheses that looks like $\left({a}^{2}-{b}^{2}\right)$ This is called a difference of squares We can factor a difference of squares like this: $\left({a}^{2}-{b}^{2}\right)=\left(a-b\right)\left(a+b\right)$ Lets