How you would solve the following equation 2x^{2}-13x-7=0 by graphing?

jelentetvq

jelentetvq

Answered question

2022-01-22

How you would solve the following equation 2x213x7=0 by graphing?

Answer & Explanation

huglaus51

huglaus51

Beginner2022-01-23Added 5 answers

Step 1
In order to solve y graphing you need some way of getting a graph without solving the equation. I'll assume that you have computer graphing software (perhaps a computer of a graphing calculator).
Solutions to
2x213x7=0
can be found by graphing the equation:
y=2x213x7
The solutions to the equation
2x2137=0
are exactly the values for x that make y=0 in y=2x213x7
On a graph, if a value for x makes y=0, then we have found an x-intercept. (and vice-versa)
So, we want to look at the graph of y=2x213x7
find the x-intercepts. Those are the solutions to
2x213x7=0
Here's the graph. There is no ''trace'' feature, but you can zoom in using your mouse wheel.
Graph: {y=2x213x7[11.34, 20.7, 9.46, 6.56]}
If looks like the solutions of y=2x213x7. (the x-intercepts of the graph of y=2x213x7)
are =12 and 7
Check that
2(12)213(12)7
and
2(7)213(7)7
give you 0.
Deegan Mullen

Deegan Mullen

Beginner2022-01-24Added 12 answers

Step 1 2x213x7=0 can be factored to (2x+1)(x7)=0 set each factor equal to zero and solve for x 2x+1=0 2x+11=01 2x=1 2x2=12 x=12 x7=0 x7+7=0+7 x=7 x=12 or 7

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