I know the length of the long sides, X.

I also know the acute, vertex angle opposite the base Y, lets

Fallbasiss4
2022-01-21
Answered

I have a non-right-angled isosceles triangle with two longer sides, X, and a short base Y.

I know the length of the long sides, X.

I also know the acute, vertex angle opposite the base Y, lets

I know the length of the long sides, X.

I also know the acute, vertex angle opposite the base Y, lets

You can still ask an expert for help

euromillionsna

Answered 2022-01-22
Author has **16** answers

Step 1

Cut the iscoles triangle in half to get a two right triangles with opposite side$\frac{1}{2}y$ and hypotenuse x.

$\frac{1}{2}Y=\mathrm{sin}\left(\frac{1}{2}a\right)x$

So apparently this is claiming

$2\mathrm{sin}\left(\frac{1}{2}a\right)=\mathrm{tan}a$

which isnt

Cut the iscoles triangle in half to get a two right triangles with opposite side

So apparently this is claiming

which isnt

ataill0k

Answered 2022-01-23
Author has **18** answers

Step 1

Bisect angle a

and

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