Solve in two different methods. (y-x+3)dx+(x+y+3)dy=0;\ x=1;\ y=4.

veksetz 2022-01-22 Answered
Solve in two different methods.
(yx+3)dx+(x+y+3)dy=0; x=1; y=4.
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Expert Answer

Navreaiw
Answered 2022-01-22 Author has 34 answers
(yx+3)dx+(x+y+3)dy=0
M=yx+3
N=x+y+3
My=1
Nx=1
 My=Nx
Its solution is
(yx+3)dx+(y+3)dy=C
 xyx22+3x+y22+3y=C
x=1, y=4
412+3+8+12=C
C=532
xyx22+3x+y22+3y=532
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