Solve the first-order differential equation State which method you are using! x^2y^2dx-(x^3+1)dy=0

prsategazd 2022-01-20 Answered
Solve the first-order differential equation State which method you are using!
x2y2dx(x3+1)dy=0
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Expert Answer

Vivian Soares
Answered 2022-01-20 Author has 36 answers

x2y2dx(x3+1)dy=0
(x3+1)dy=x2y2dx

dyy2=(x2x3+1)dx
Variable separable for
1y2dy=x2x3+1dx
1y2dy=133x2x3+1dx
1y=13ln(x3+1)+c
1y=13ln(x3+1)+c1
or
y=3ln(x3+1)+c2

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