Write an equivalent​ first-order differential equation and initial condition for

b2sonicxh 2022-01-21 Answered

Write an equivalent​ first-order differential equation and initial condition for y.
y=1+0x(2t5y(t))dt
What is the equivalent first-order differential equation?
y=?
What is the initial condition?
y(y=?)=?

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Expert Answer

Elois Puryear
Answered 2022-01-21 Author has 30 answers
Given,
y=1+0x(2t5y(t))dt
Differentiating both side, we get
y=0+2x5y(x)
  y=2x5y(x)
Since, y(x)=1+0x(2t5y(t))dt
  y(0)=1+00(2t5y(t))dt=1+0  [ aaf(x)dx=0]
  y(0)=1

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