Yasmin
2020-11-30
Answered

Use Cramers

You can still ask an expert for help

diskusje5

Answered 2020-12-01
Author has **82** answers

Step 1

Given: The system of equations is

2x+3y=4

4x-6y=8

Step 2

Solution:

Obtain the value of D as follows.

$D\left|\begin{array}{cc}2& 3\\ 4& -6\end{array}\right|$

=2(-6)-(3)(4)

=-12-12

$=-24\ne 0$

As D is not equal to zero, the unique solution exists.

Step 3

Obtain the value of$D}_{1$ as follows.

${D}_{1}=\left|\begin{array}{cc}4& 3\\ 8& -6\end{array}\right|$

=(4)(-6)-3(8)

=-24-24

=-48

Step 4

Obtain the value of$D}_{2$ as follows.

${D}_{2}=\left|\begin{array}{cc}2& 4\\ 4& 8\end{array}\right|$

=2(8)-(4)(4)

=16-16

=0

Step 5

Thus, the value of x and y by Cramer’s rule becomes

$x=\frac{{D}_{1}}{D}=\frac{-48}{-24}=2$

$y=\frac{{D}_{2}}{D}=\frac{0}{-24}=0$

Step 6

Therefore, the solution of the system of equations is

x=2 and y =0

Given: The system of equations is

2x+3y=4

4x-6y=8

Step 2

Solution:

Obtain the value of D as follows.

=2(-6)-(3)(4)

=-12-12

As D is not equal to zero, the unique solution exists.

Step 3

Obtain the value of

=(4)(-6)-3(8)

=-24-24

=-48

Step 4

Obtain the value of

=2(8)-(4)(4)

=16-16

=0

Step 5

Thus, the value of x and y by Cramer’s rule becomes

Step 6

Therefore, the solution of the system of equations is

x=2 and y =0

Jeffrey Jordon

Answered 2021-11-11
Author has **2262** answers

Answer is given below (on video)

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To solve