Solve: \frac{dy}{dx}-\frac{dx}{dy}=\frac{y}{x}-\frac{x}{y}

hadejada7x 2022-01-20 Answered
Solve: dydxdxdy=yxxy
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Expert Answer

raefx88y
Answered 2022-01-20 Author has 26 answers
If u and v are real numbers 0 then
v1v=u1u
holds if either v=u or v=1u.

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Elaine Verrett
Answered 2022-01-21 Author has 41 answers
xy(dydx)2dydxy2+dydxx2xy=0
y(dydx)(x(dydx)y)+x(x(dydx)y)=0
(x(dydx)y)(y(dydx)+x)=0
dydx=xyydy=xdx
and dydx=yxdyy=dxx

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RizerMix
Answered 2022-01-27 Author has 438 answers
v1v=u1u u,v0 and vu=1v1u=vuuv u=c0 or uv=1 (i.e.v=δuδ0 for δ=±1) Now dydx and dxdy are reciprocals, so dydxdxdy=yxxy dydx=yx or dydx=xy dyy=dxx or ydy=xdx ln|y|=ln|x|+c1 or y22=x22+c2 y=(±ec1)x or y2=x2+2c2 y=ax or y2=x2+b

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