Solve the following system of equations. 2x_1−x_2−x_3=−3 3x_1+2x_2+x_3=13 x_1+2x_2+2x_3=11 (x_1, x_2, x_3) =

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Answered question

2021-01-13

Solve the following system of equations.
2x1x2x3=3
3x1+2x2+x3=13
x1+2x2+2x3=11
(x1,x2,x3)=

Answer & Explanation

Theodore Schwartz

Theodore Schwartz

Skilled2021-01-14Added 99 answers

Step 1
Let x_1=x , x_2=y and x_3=z
So, the equations are:
2x-y-z=-3
3x+2y+z=13
x+2y+2z=11
Step 2
Let use eliminate z first. Add first two equations. That gives 5x+y=10
Step 3
Multiply first equation by 2 and add it to the third equation.
2(2xyz=3)4x2y2z=6
Add it to x+2y+2z=11
So we get 5x=5
So, x=55=1
Step 4
We had 5x+y=10
Here we plug x=1 and find y
5(1)+y=10
Or, 5+y=10
Or, y=5
Step 5
In 2x-y-z=-3 we plug x=1 and y=5 and find z
2(1)-5-z=-3
Or, 2-5-z=-3
Or, -3-z=-3
Or, z=0
Result: (x1,x2,x3)=(1,5,0)

Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-11Added 2605 answers

Answer is given below (on video)

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