# What is the solution to this system of equations? 3x-y+5=0 2x+3y-4=0

What is the solution to this system of equations?
3x-y+5=0
2x+3y-4=0
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Step 1
Name the two equations as (1) and (2),
3x-y+5=0...(1)
2x+3y-4=0...(2)
Reframe equation (1) in the form y=mx+c
y=3x+5...(3)
Step 2
Substitute equation (3) in equation (2) and solve for x,
2x+3(3x+5)-4=0
2x+9x+15-4=0
11x+11=0
$x=-\frac{11}{11}$
x=-1
Step 3
Substitute value of x in equation (3),
y=3(-1)+5
y=2
Step 4
Hence the solution to the system of equations above is (-1,2)
Jeffrey Jordon