# Solve the system of equations. 3(x-y)=y-3 -2x+y/2=-11

Solve the system of equations.
3(x-y)=y-3
$-2x+\frac{y}{2}=-11$
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Clara Reese
Step 1
Given the system of equations
3(x-y)=y-3
$-2x+\frac{y}{2}=-11$
Step 2
Simplify the both of equations
3x-3y=y-3
3x-4y=-3...(1)
and
$-2x+\frac{y}{2}=-11$
-4x+y=-22...(2)
Step 3
Multiply equation (2) with 4
-16x+4y=-88...(3)
Step 4
Add the equation (1) and (3)
3x-16x=-3-88
-13x=-91
x=7
Step 5
Plug the value of x in equation (2)
-4(7)+y=-22
-28+y=-22
y=6
Step 6
Therefore,
x=7
y=6
Jeffrey Jordon