Solve the system of equations. 4x+y=16 2x+3y=18

Solve the system of equations.
4x+y=16
2x+3y=18
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Arnold Odonnell

Step 1
To solve the given equations by substitution method.
Step 2
Given information:
4x+y=16...(1)
2x+3y=18...(2)
Step 3
Calculation:
Simplify equation (1).
4x+y=16...(1)
4x-4x+y=16-4x
y=16-4x...(3)
Step 4
Substitute y=16-4x in equation (1).
2x+3y=18
2x+3(16-4x)=18
2x+48-12x=18
-10x+48=18 $\left[\sim pl\phantom{\rule{1em}{0ex}}\text{if}\phantom{\rule{1em}{0ex}}y\right]$
-10x=18-48
-10x=-30

x=3
Step 5
Substitute x= 3 in equation (3).
y=16-4x...(3)
y=16-4(3)
y=16-12
y=4
Thus, the solution of system equations is x= 3 and y= 4.

Jeffrey Jordon