Solve the following system of Equations. -2x^2-y^2=-200 -3x^2-y^2=-300

Jaden Easton 2020-11-30 Answered
Solve the following system of Equations.
2x2y2=200
3x2y2=300
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Expert Answer

Nathalie Redfern
Answered 2020-12-01 Author has 99 answers
Step 1
Given the system of equations.
2x2y2=200...(1)
3x2y2=300...(2)
Step 2
Subtracting equation (1) and (2)
2x2y2(3x2y2)=200300
2x2y2+3x2+y2=100
2x2+3x2=100
x2=100
x2=(i10)2
x=±10i
Putting the value x2 in equation (1)
2(100)y2=200
200y2=200
y2=200200
y2=0
Solution of the given system is
x=-10i,10i and y = 0,0
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Jeffrey Jordon
Answered 2021-11-08 Author has 2064 answers

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