Solve the following system of Equations. -2x^2-y^2=-200 -3x^2-y^2=-300

Jaden Easton

Jaden Easton

Answered question

2020-11-30

Solve the following system of Equations.
2x2y2=200
3x2y2=300

Answer & Explanation

Nathalie Redfern

Nathalie Redfern

Skilled2020-12-01Added 99 answers

Step 1
Given the system of equations.
2x2y2=200...(1)
3x2y2=300...(2)
Step 2
Subtracting equation (1) and (2)
2x2y2(3x2y2)=200300
2x2y2+3x2+y2=100
2x2+3x2=100
x2=100
x2=(i10)2
x=±10i
Putting the value x2 in equation (1)
2(100)y2=200
200y2=200
y2=200200
y2=0
Solution of the given system is
x=-10i,10i and y = 0,0
Jeffrey Jordon

Jeffrey Jordon

Expert2021-11-08Added 2605 answers

Answer is given below (on video)

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