# Solve the following system of Equations. -2x^2-y^2=-200 -3x^2-y^2=-300

Solve the following system of Equations.
$-2{x}^{2}-{y}^{2}=-200$
$-3{x}^{2}-{y}^{2}=-300$
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

Nathalie Redfern
Step 1
Given the system of equations.
$-2{x}^{2}-{y}^{2}=200$...(1)
$-3{x}^{2}-{y}^{2}=300$...(2)
Step 2
Subtracting equation (1) and (2)
$-2{x}^{2}-{y}^{2}-\left(-3{x}^{2}-{y}^{2}\right)=200-300$
$-2{x}^{2}-{y}^{2}+3{x}^{2}+{y}^{2}=-100$
$-2{x}^{2}+3{x}^{2}=-100$
${x}^{2}=-100$
${x}^{2}={\left(i10\right)}^{2}$
$x=±10i$
Putting the value ${x}^{2}$ in equation (1)
$-2\left(-100\right)-{y}^{2}=200$
$200-{y}^{2}=200$
${y}^{2}=200-200$
${y}^{2}=0$
Solution of the given system is
x=-10i,10i and y = 0,0
###### Not exactly what you’re looking for?
Jeffrey Jordon

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee