osnomu3
2022-01-17
Answered

What are the mean and standard deviation of a binomial probability distribution with n=2 and $p=\frac{4}{17}$ ?

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veiga34

Answered 2022-01-17
Author has **32** answers

The mean is $\mu =n\cdot p=2\cdot \frac{4}{17}=\frac{8}{17}\approx 0.4706$ and the standard deviation is

$\sigma =\sqrt{n\cdot p\cdot (1-p)}=\sqrt{2\cdot \frac{4}{17}\cdot \frac{13}{17}}=\sqrt{\frac{104}{289}}\approx 0.5999$

Explanation:

The special formulas$\mu =n\cdot p$ and $\sigma =\sqrt{n\cdot p\cdot (1-p)}$ only work for binomial random variables, where n is the number of independent trials with outcomes success or failure, and p is the probability of success on each trial. The random variable X itself counts the number of successes in n trials.

Explanation:

The special formulas

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