b2sonicxh
2022-01-18
Answered

What are the mean and standard deviation of a binomial probability distribution with n=21 and $p=\frac{4}{17}$ ?

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Mary Goodson

Answered 2022-01-18
Author has **37** answers

Explanation:

For Binomial Probability Distribution

The Mean$=np=21\left(\frac{4}{17}\right)=\frac{84}{17}$

Standard Deviation

$=\sqrt{npq}=\sqrt{np(1-p)}=\sqrt{21\left(\frac{4}{17}\right)(1-\frac{4}{17})}=1.94$

For Binomial Probability Distribution

The Mean

Standard Deviation

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