eozoischgc
2022-01-17
Answered

What are the mean and standard deviation of a binomial probability distribution with n=13 and $p=\frac{5}{24}$ ?

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accimaroyalde

Answered 2022-01-17
Author has **29** answers

Explanation:

Binomial distribution is a frequency distribution of possible number of successful outcomes in given number of trials n, in each of which there is the probability of success is p (and q=1-p is probability of failure)

The mean and standard deviation of a binomial distribution are given by np and$\sqrt{npq}$ .

Here$n=13,p=\frac{5}{24}$ and $q=1-\frac{5}{24}=\frac{19}{24}$ .

Hence mean is$13\times \frac{5}{24}=2.708$

Standard deviation is$\sqrt{13\times \frac{5}{24}\times \frac{19}{24}}$

$=\frac{1}{24}\times \sqrt{1235}=\sqrt{4.8696}=1.464$

Binomial distribution is a frequency distribution of possible number of successful outcomes in given number of trials n, in each of which there is the probability of success is p (and q=1-p is probability of failure)

The mean and standard deviation of a binomial distribution are given by np and

Here

Hence mean is

Standard deviation is

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