Explanation:
Method 1
If we start with a full deck there are 52 cards; 4 aces; 48 non-aces
Card 1 deal should not be an Ace (48 non aces; 52 cards)
P(Card 1 not Ace)
Card 2 deal should not be an Ace (47 non aces; 51 cards)
P(Card 2 not Ace)
Card 3 deal should not be an Ace (46 non aces; 50 cards)
P(Card 3 not Ace)
Card 4 deal should not be an Ace (45 non aces; 49 cards)
P(Card 4 not Ace)
Card 5 deal should not be an Ace (44 non aces; 48 cards)
P(Card 5 not Ace)
So then:
P(all five cards non aces)
=0.658841...
Method 2
Using the combination formula:
The number of combination of choosing five non-aces from 52 cards (48 of which are not aces) is given by:
n(all five cards non aces)
And the total number of all combinations of choosing any five cards
n(any five cards)
P (all five cards non aces)
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