Solve the system of equations: 3x - y = -2, 2x^2 - y = 0

defazajx 2020-12-22 Answered
Solve the system of equations: 3xy=2,2x2y=0
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Expert Answer

odgovoreh
Answered 2020-12-23 Author has 107 answers
Step 1
Given: The system of equations
3x−y=−2
2x2y=0
To find: The solution of given system of equation.
Step 2
Explanation:
Let
3x−y=−2 ...(i)
2x2y=0 ...(ii),
From equation (i),
3x−y=−2,
y=3x+2
Substituting y=3x+2 in equation (ii),
2x2y=0
2x2(3x+2)=0
2x23x2=0
2x24x+x2=0
(x2)(2x+1)=0
x=2,12
Now,
For x=2,y=3×2+2=8,
For x=12,y=3×(12)+2=32+2=12
Hence x=2, y=8 and x=12,y=12 are solution of given system of equations.
Result: x=2, y=8 and x=12,y=12 are solution of given system of equation.
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