Solve the system of equations: 3x - y = -2, 2x^2 - y = 0

defazajx

defazajx

Answered question

2020-12-22

Solve the system of equations: 3xy=2,2x2y=0

Answer & Explanation

odgovoreh

odgovoreh

Skilled2020-12-23Added 107 answers

Step 1
Given: The system of equations
3x−y=−2
2x2y=0
To find: The solution of given system of equation.
Step 2
Explanation:
Let
3x−y=−2 ...(i)
2x2y=0 ...(ii),
From equation (i),
3x−y=−2,
y=3x+2
Substituting y=3x+2 in equation (ii),
2x2y=0
2x2(3x+2)=0
2x23x2=0
2x24x+x2=0
(x2)(2x+1)=0
x=2,12
Now,
For x=2,y=3×2+2=8,
For x=12,y=3×(12)+2=32+2=12
Hence x=2, y=8 and x=12,y=12 are solution of given system of equations.
Result: x=2, y=8 and x=12,y=12 are solution of given system of equation.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?