Randomly drawing three green skittles in a row from a

reproacht3

reproacht3

Answered question

2022-01-19

Randomly drawing three green skittles in a row from a bag that contains eight green skittles out of 25 skittles total.

Answer & Explanation

lenkiklisg7

lenkiklisg7

Beginner2022-01-19Added 29 answers

Step 1
Given that a bag contains 25 skittles in which eight are green. Three green skittles are drawn from the bag in a row
and the skittles are drawn eaten immediately.
Therefore,
Total number of skittles are 25 and total number of green skittles are 8.
Step 2
Probability that the 1st skittle drawn from the bag is green will be number of green skittles/ total number of skittles =825
The 1st drawn skittle have been eaten therefore there are total 24 skittles are left in which 7 skittles are green.
Probability that the 2nd skittle drawn from the bag is green will be number of green skittles after 1st draw/ total number of skittles after 1st draw =724
The 2nd drawn skittle eaten immediately therefore there are total 23 skittles are left in which 6 skittles are green.
Probability that the 3rd skittle drawn from the bag is green will be number of green skittles after 2nd draw/ total number of skittles after 2nd draw =623
Step 3
Probability (p) that the three green skittles are drawn in a row can be obtained as follows.
p=Probability that the 1st skittle drawn from the bag is green ×
Probability that the 2nd skittle drawn from the bag is green after 1st draw ×
Probability that the 3rd skittle drawn from the bag is green after 2nd draw
=825×724×623
0.0243
Therefore probability that the three green skittles are drawn in a row is approximately 0.0243.

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