b2sonicxh
2022-01-17
Answered

As Mark Ellon is getting ready for a meeting, the room goes dark. He fishes for a green shirt in his drawer. He wears only blue, green and white colors. His drawers have identical shirts in these colors: 28 blue, 25 green, and 13 white shirts. How many shirts did he throw on the floor to be a cent percent sure that he has a taken out a green shirt?

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peterpan7117i

Answered 2022-01-17
Author has **39** answers

Step 1

Given:

Number of blue shirts is, n(B)=28.

Number of green shirts is, n(G)=25.

Number of white shirts is, n(W)=13.

The objective is to find the number of shirts that he must throw on the floor to be a cent percent sure that he has a taken out a green shirt.

Step 2

The total number of shirts can be calculated as,

N=n(B)+n(G)+n(W)

=28+25+13

=66

Number of non green shirts are,

n(G)=n(B)+n(W)

=28+13

=41

Thus, there are 41 non green shirts in the drawer. So the person must throw 41 shirts on the floor to make a cent percent sure that 42nd shirt is green shirt.

Hence, the number of shirts that the person must throw on the floor is 41.

Given:

Number of blue shirts is, n(B)=28.

Number of green shirts is, n(G)=25.

Number of white shirts is, n(W)=13.

The objective is to find the number of shirts that he must throw on the floor to be a cent percent sure that he has a taken out a green shirt.

Step 2

The total number of shirts can be calculated as,

N=n(B)+n(G)+n(W)

=28+25+13

=66

Number of non green shirts are,

n(G)=n(B)+n(W)

=28+13

=41

Thus, there are 41 non green shirts in the drawer. So the person must throw 41 shirts on the floor to make a cent percent sure that 42nd shirt is green shirt.

Hence, the number of shirts that the person must throw on the floor is 41.

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