My work with complex numbers verified that the only possible

Step 1
Concept:
The calculus helps in understanding the changes between values that are related by a function. It is used in different areas such as physics, biology and sociology and so on. The calculus is the language of engineers, scientists and economics.
Step 2
Given:
It is given that,''My work with complex numbers verified that the only possible cube root of 8 is 2''
The objective is to check that the sentence make sense or not
Step 3
This given statement does not makes sense
Here DeMoivre's theorem for roots applies to complex numbers in polar form. Thus writing the given term in terms of polar form that is 8 or ${\displaystyle 8+0i}$ in the polar form Expressing ${\displaystyle \theta }$ in radians although degrees could also be used
${\displaystyle 8=r(\cos \theta +i\sin \theta )=8(\cos 0+i\sin 0)}$
There is three cube root exactly of 8. From DeMoivre's theorem for finding complex roots, the cube roots of 8 are
$Z_k=\sqrt[3]{8}(\cos (\frac{0+2\pi k}{3})+i\sin (\frac{0+2\pi k}{3}))$
${\displaystyle k=0,1,2}$
Step 4
The cube roots of 8 are found by substituting 0, 1, 2 for k in the above expression
$Z_0=\sqrt[3]{8}(\cos (\frac{2\pi 0}{3})+i\sin (\frac{2\pi 0}{3}))$
${\displaystyle Z_0=2\left({\cos 0}^0+i{\sin 0}^0\right)\Rightarrow }$ Polar form
${\displaystyle Z_0=2\Rightarrow }$ rectangular form
${\displaystyle Z_1=2(\cos \left(\frac{2\pi }{3}\right)+i\sin \left(\frac{2\pi }{3}\right))}$
${\displaystyle Z_1=2\left({\cos 120}^{\circ }+i{\sin 120}^{\circ }\right)}$
Thus polar form,
${\displaystyle Z_1=2\left({\cos 120}^{\circ }+i{\sin 120}^{\circ }\right)}$
The rectangular form
${\displaystyle Z_1=2(\frac{1}{2}+i\frac{\sqrt{3}}{2})}$
Step 5
$Z_2=\sqrt[3]{8}(\cos (\frac{4\pi }{3}{)}_i\sin (\frac{4\pi }{3}))$
${\displaystyle Z_2=2\left({\cos 240}^{\circ }+i{\sin 240}^{\circ }\right)}$
polar form
${\displaystyle Z_2=2(-{\cos 60}^{\circ }-i{\sin 60}^{\circ })}$
Rectangular form
${\displaystyle Z_2=-2(\frac{\sqrt{3}}{2}+i\frac{1}{2})}$