Step 1

Since you have asked multiple question, we will solve the first question for you.

If you want any specific question to be solved then please specify the question number or post only that question.

Step 2

(1)

The given system of linear equations are

x−y=2 ...(1)

x+y=8 ...(2)

The given ordered pair for this system is (5, 3).

The ordered pair is the solution of the system it must be satisfy both the equations.

Step 3

Substitute x=5 and y=3 in the left side of the equation (1).

LHS=x-y

=5-3

=2

RHS

Substitute x=5 and y=3 in the left side of the equation (2).

LHS=x+y

=5+3

=8

=RHS

Since the ordered pair satisfies the system of linear equations.

Hence, the ordered pair (5, 3) is a solution to the given system of linear equations.

Since you have asked multiple question, we will solve the first question for you.

If you want any specific question to be solved then please specify the question number or post only that question.

Step 2

(1)

The given system of linear equations are

x−y=2 ...(1)

x+y=8 ...(2)

The given ordered pair for this system is (5, 3).

The ordered pair is the solution of the system it must be satisfy both the equations.

Step 3

Substitute x=5 and y=3 in the left side of the equation (1).

LHS=x-y

=5-3

=2

RHS

Substitute x=5 and y=3 in the left side of the equation (2).

LHS=x+y

=5+3

=8

=RHS

Since the ordered pair satisfies the system of linear equations.

Hence, the ordered pair (5, 3) is a solution to the given system of linear equations.