Finding n if |\sum_{r=0}^{3n-1} \beta^{2^r}|=4\sqrt2 where \beta=\exp(\frac{i 2 \pi}{7})

Walter Clyburn

Walter Clyburn

Answered question

2022-01-17

Finding n if |r=03n1β2r|=42 where β=exp(i2π7)

Answer & Explanation

Robert Pina

Robert Pina

Beginner2022-01-18Added 42 answers

Let z=β+β2+β4, then z=β3+β5+β6. Notice that β7=1 and β+β2+β3+β4+β5+β6=1.
So |z|2=zz=(β+β2+β4)(β3+β5+β6)=β4+β6+β7+β5+β7+β8+β7+β9+β10=3+β+β2+β3+β4+β5+β6=2
Thus |β+β2+β4|=2, and we have n=4.

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