An object of mass m attached to a spring of force constant k

Wanda Kane

Wanda Kane

Answered question

2022-01-14

An object of mass m attached to a spring of force constant k oscillates with simple harmonic motion. The maximum displacement from equilibrium is A and the total mechanical energy of the system is E.
What is the objects

Answer & Explanation

poleglit3

poleglit3

Beginner2022-01-15Added 32 answers

Here we have the equation for maximum velocity
vmax=km×A
We are given eith potential energy
P.E=23E
Sokinetic ebegry will be
K.E=13E
So the required velocity when P.E=23E
v=13×vmax
=km×A3
vicki331g8

vicki331g8

Beginner2022-01-16Added 37 answers

Another solution?
alenahelenash

alenahelenash

Expert2022-01-23Added 556 answers

As we know that total energy of SHM is always constant so here we know that total energy = Kinetic energy + potential energy so here we have potential energy = 2/3E so we will have kinetic energy as KE=E23E now we have KE=13E now for the speed of the block 12mv2=13E by solving above equation we have v=2E3m

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