A 15.6-g mixture of nitrogen and carbon dioxide

Answered question

2022-01-19

A 15.6-g mixture of nitrogen and carbon dioxide is found to occupy a volume of 9.9L when measured at 940.2 mmHg and 54.9°C. What is the mole fraction of carbon dioxide in this mixture?

Answer & Explanation

nick1337

nick1337

Expert2022-02-01Added 777 answers

Calculate the total moles in the mixture using the ideal gas equation as follows

n=PVRT

n=(940.2760atm)×9.9L0.08215LatmmalK×(54.9+273)K

n=0.455mol

Molar mass of N2=28g/mol

 Molar mass of CO2=44g/mol

Suppose mass of CO2=x

So, mass of N3=(16.6x)

Total miles is calculated as follows

x44g/mol+15.6x28g/mol=0.455mol

28x+15.6×4444x=44×28×0.455

x=7.865g

Mole fraction of CO2 is calculated as

7.8654415.67.86528+7.86544

=0.40

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