Raul has 56 bouncy balls. He puts the balls into 4 green gift bags. If he puts the same number of balls into each bag, how many balls does he put into each green bag?

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Esta Hurtado · Accepted Answer

We have to calculate 56÷4: 144)56. Divide integers 5÷4=1 144)56―−4―     16 −16―        0 Divide integers 5÷4=1 Multiply 1⋅4=4. Then subtract. Write down 6 and divide integers 16÷4=4. Multiply 4⋅4=16. Then subtract.

Chanell Sanborn · Accepted Answer

Green bags must hold 1/4th of the balls (as we divided them, by color, in the ratio 3:1). Thus there a 14 balls in the green bags, hence 42 in the red bags.  Findind the number of ball in each bag  Well, whatever that number is it must divide both 14 and 42, hence it is a common factor of those two numbers. But we can list those common factor (1,2,7,14). Each of these gives us a solution!  1. 1 ball in each of 14 green and 42 red bags.  2. 2 ball in each of 7 green and 21 red bags.  3. 7 balls in each of 2 green and 6 red bags.  4. 14 balls in each of 1 green and 3 red bags. (Unless you interpret the problem as requiring plural green bags.)

star233 · Accepted Answer

If we divide 56 by 4 we get 14. Why by 4? So that one number is 3 times the other. So he had 14 balls that went into the green bags and 42 (56-14) that went into the red bags. We could just answer the question and say 14 but I think they want to know how many in each green bag. 14 and 42 don&#039;t work because they are not the same number of balls. What number is a common factor? 7 is, We could have 2 green bags and split the 14 balls into 2 groups of 7 and with the remaining 42 - put them into 6 red bags of 7 each. And so the answer to your question is: 7ball in each bag=2bags are green, and 6 bags are red 14 balls+42 balls=56 bouncy balls

Raul has 56 bouncy balls. He puts the balls into

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