How many liters of a 0.0550 M KCl solution contain 0.163 moles KCl?

Question

Orlando Paz · Accepted Answer

Step 1 Given: Molarity of KCl =0.0550M Moles=0.163 moles Step 2 Molarity= number of moles / volume of solution(L) 0.0550 molL−1=0.1623 moles / volume of solution Volume of solution =2.96L Step 3 Conclusion : Volume of HCl solution =2.96L

Mason Hall · Accepted Answer

2.9636 Liters, and this can be proved by multiplying the top and bottom of the ratio of

.0550 m o l \frac{K C L}{1}

L by this amount. (This is allowed because you are multiplying the top and bottom by the same number, and thus it would be equivalent to multiplying this by 1).
Hope that helps.. and if you have to show work then just set up a proportion in which you set the ratio

.0550 m o l \frac{K C L}{1}

Liters equal to

.163 m o l \frac{K C L}{X}

Liters.
Source(s): having taken AP Chem

star233 · Accepted Answer

Step 1
Molarity (M) of a solution is defined as the number of moles of solute dissolved per volume of the solution in liter. i.e.
$Milarity(M) = \frac{Number of moles of solute}{Volume of solution (in L)}$
or, volume of solution (in L) $= \frac{Number of moles of solute}{Molarity}$
Step 2
We have, molarity of KCl solution = 0.0550 M = 0.0550 mol/L
and, moles of KCl = 0.163 mol
Thus, volume of solution $= \frac{0.163 m o l}{0.0550 m o l / L}$
=2.96L
Therefore, the liters of KCl solution is 2.96 L.

How many liters of a 0.0550 M KCl solution contain

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