Both HCO^{-}_{3} and HS^{-} are amphoteric. Write an equation

William Burnett 2022-01-12 Answered
Both \(\displaystyle{H}{C}{O}^{{-}}_{\left\lbrace{3}\right\rbrace}\) and \(\displaystyle{H}{S}^{{-}}\) are amphoteric. Write an equation to show how each substance can act as an acid and another equation to show how each can act as a base.

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Expert Answer

Ronnie Schechter
Answered 2022-01-13 Author has 54 answers

\(HCO_3^{-}(ag) + HS(ag) \rightleftharpoons CO_3^{2-}(ag) + H_2S(aq)\)
Let \(\displaystyle{H}{C}{O}^{{-}}_{\left\lbrace{3}\right\rbrace}\) be a \(Br\emptyset\) nsted-Lowry acid and let \(HS^{-}\) be a \(Br\emptyset\) nsted-Lowry base. The conjugate base of the acid is then determined by removing an H atom and
a unit of positive charge. The conjugate acid of the base is then determined by adding an H atom anda unit of positive charge.
\(HCO_3^{-}(ag) + HS^{-}(ag) \rightleftharpoons H_2CO_3(ag) + S^{-2}(aq)\)
Let \(\displaystyle{H}{C}{O}^{{-}}_{\left\lbrace{3}\right\rbrace}\) be a ​​​​​​​\(Br\emptyset\) nsted-Lowry base and let \(HS^{-}\)
be a \(Br\emptyset\) nsted-Lowry acid. The conjugate acid of the
base is then determined by adding an H atom anda unit of positive charge. The conjugate base of the acid is then determined by removing an H atom and a unit of positive charge.

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soanooooo40
Answered 2022-01-14 Author has 803 answers

Explanation:
According to Bronsted and Lowry an acid is a proton donor and base is a proton acceptor.
Therefore, the equation for the reaction will be as follows.
\(HCO^{-}_{3}+ HS^{-}= H_{2}CO_{3} +S^{2} t\)
Here, \(\displaystyle{H}{C}{O}^{{-}}_{\left\lbrace{3}\right\rbrace}\) acts as a base as it is accepting a proton and \(\displaystyle{H}{S}^{{-}}\) acts as an acid because it is donating a proton.

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