A 14-gauge copper wire of diameter 1.628 mm carries a current of 12.5

Deragz

Deragz

Answered question

2022-01-11

A current of 12.5 mA is carried via a copper wire of 14-gauge with a diameter of 1.628 mm.
(a) What is the potential difference across a 2.00-m length of the wire? 
(b) What would the potential difference in part (a) be if the wire were silver instead of copper, but all else were the same?

Answer & Explanation

autormtak0w

autormtak0w

Beginner2022-01-12Added 31 answers

Step 1
Given that:
d=1.628mm=1.628×103m,I=12.5mA=12.5×103A
The Cross-sectional area of the wire is:
A=π4d2
=π4×(1.628×103m)2
=2.082×106m2
a) The Potential difference across a 2.00m length of a 14-gauge copper wire:
L=2.00m
From Table 25.1: Copper Resistivity ρ=1.72×108Ωm
The Resistance of the Copper wire is:
R=ρLA
=(1.72×108Ωm)(2.00m)2.082×106m2
=0.0165Ω
The Potential difference across the copper wire is:
V=IR
=(12.5×103A)×(0.0165Ω)
=2.063×104V
Step 2
b) The Potential difference if the wire were made of Silver:
From Table 25.1: Silver Resistivity ρ=1.47×108Ωm
The Resistance of the Silver wire is:
R=ρLA
=(1.47×108Ωm)(2.00m)2.082×106m2
=0.014Ω
The Potential difference across the Silver wire is:
V=IR
=(12.5×103A)×(0.014Ω)
=1.75×104V
Barbara Meeker

Barbara Meeker

Beginner2022-01-13Added 38 answers

Step 1
The diameter of the copper wire is, d=1.628mm=1.628×103m
The current carried by the wire is 12.5 mA, I=12.5×103A
The resistance across a wire of length L and cross sectional area A is given as R=ρLA
ρ is the resistivity of the material
The length of the wire is, L=2m
The cross sectional area of the wire will be
A=πr2
r is the radius of the wire, r=d2=0.814×103m
A=π(0.814×103)2
A=2.0816×106m2
Step 2
For copper, ρ=1.68×108Ωm
R=1.68×108×22.0816×106
R=0.016Ω
This is resistance for the given copper wire
From Ohms

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