Use Avogadro’s number to find the mass of a helium atom.

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Annie Gonzalez · Accepted Answer

Step 1 Avogardo&#039;s number is NA=6.02×1023 particles/mol. A mole of anything, by definition, consists of an Avogadro&#039;s number of particles. The mass M of one mole of a pure substance in grams is the same, numerically, as that substance&#039;s atomic (or molecular) mass. The mass of a single molecule is then  m=MNA. Use the table in Appendix B: For helium, M=4.00gmol=4.00×10−3kgmol. So, the mass of a helium molecule is Step 2 m=4.00×103kg/mol6.02×1023molecule/mol=6.64×10−27kg/molecule. Since a helium molecule contains a single helium atom, the mass of a helium atom is m=6.64×10−27kg

Debbie Moore · Accepted Answer

One mole of helium contains Avogadro&#039;s number of molecules and has a mass of 4.00g. Let us call m0 the mass of one atom, and we have NAm0=4.00gmol or m0=4.00gmol6.02×1023molecule/mol=6.64×10−24g/molecule, =6.64×10−27kg

Use Avogadro’s number to find the mass of a helium

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