Find the similarity ratio of two triangles with areas 81 feet^2 and 100 feet^2.

Find the similarity ratio of two triangles with areas $81fee{t}^{2}\phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}100fee{t}^{2}$.
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Demi-Leigh Barrera
Step 1
Let the area of two similar triangles be $A1=81fee{t}^{2}\phantom{\rule{1em}{0ex}}\text{and}\phantom{\rule{1em}{0ex}}A2=100fee{t}^{2}$
Hence, the similarity ratio $={\left(A\frac{1}{A}2\right)}^{\frac{1}{2}}$
Step 2
Hence, the similarity ratio $={\left(\frac{81}{100}\right)}^{\frac{1}{2}}=\frac{9}{10}=0.9$
Step 3
Hence, the final answer is $\frac{9}{10}$ or 0.9