Find the similarity ratio of two triangles with areas 81 feet^2 and 100 feet^2.

Question

Find the similarity ratio of two triangles with areas

81 f e e t^{2} and 100 f e e t^{2}

.

Answer 1

Step 1
Let the area of two similar triangles be

A 1 = 81 f e e t^{2} and A 2 = 100 f e e t^{2}

Hence, the similarity ratio

= {(A \frac{1}{A} 2)}^{\frac{1}{2}}

Step 2
Hence, the similarity ratio

= {(\frac{81}{100})}^{\frac{1}{2}} = \frac{9}{10} = 0.9

Step 3
Hence, the final answer is

\frac{9}{10}

or 0.9

Expert Answer