The equation above gives the monthly cost C, in dollars, to take care of k kittens and b bunnies. John has 3 kittens and 5 bunnies, and Jenny has 2 ki

Yulia 2020-12-03 Answered
The equation above gives the monthly cost C, in dollars, to take care of k kittens and b bunnies. John has 3 kittens and 5 bunnies, and Jenny has 2 kittens and 3 bunnies. How much greater, in dollars, is Johns
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estenutC
Answered 2020-12-04 Author has 81 answers

The total cost in dollars is,
52k+34b=c
where k is the number of kittens and b is the number of bunnies.
John has 3 kittens and 5 bunnies.
To find total cost of John, substitute k=3 and b=5 in the given equation, we get
52(3)+34(5)=C
C=$326
Jenny has 2 kittens and 3 bunnies.
To find total cost of Jenny, substitute k=2 and b=3 in the given equation, we get
52(2)+34(3)=C
C=$206
Now the difference in cost is,
$326$206=$120
Hence John's total cost is $120 greater than the Jenny's total cost.

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