# The equation above gives the monthly cost C, in dollars, to take care of k kittens and b bunnies. John has 3 kittens and 5 bunnies, and Jenny has 2 ki

The equation above gives the monthly cost C, in dollars, to take care of k kittens and b bunnies. John has 3 kittens and 5 bunnies, and Jenny has 2 kittens and 3 bunnies. How much greater, in dollars, is Johns
You can still ask an expert for help

• Questions are typically answered in as fast as 30 minutes

Solve your problem for the price of one coffee

• Math expert for every subject
• Pay only if we can solve it

estenutC

The total cost in dollars is,
$52k+34b=c$
where k is the number of kittens and b is the number of bunnies.
John has 3 kittens and 5 bunnies.
To find total cost of John, substitute $k=3$ and $b=5$ in the given equation, we get
$52\left(3\right)+34\left(5\right)=C$
$⇒C=\mathrm{}326$
Jenny has 2 kittens and 3 bunnies.
To find total cost of Jenny, substitute $k=2$ and $b=3$ in the given equation, we get
$52\left(2\right)+34\left(3\right)=C$
$⇒C=\mathrm{}206$
Now the difference in cost is,
$326-206=120$
Hence John's total cost is \$120 greater than the Jenny's total cost.