Find the first partial derivatives of the following functions. s(y, z) = z^2 tan yz

Amari Flowers 2021-03-09 Answered
Find the first partial derivatives of the following functions.
s(y,z)=z2tanyz
You can still ask an expert for help

Want to know more about Derivatives?

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more

Solve your problem for the price of one coffee

  • Available 24/7
  • Math expert for every subject
  • Pay only if we can solve it
Ask Question

Expert Answer

pattererX
Answered 2021-03-10 Author has 95 answers
Step 1
Consider the provided function,
S(y,z)=z2tanyz
Find the first partial derivatives.
So, we find the expression for SyandSz.
First we find the expression for Sy.
Sy=y(z2tanyz)
Step 2
Simplifying further,
Sy=y(z2tanyz)
=z2y(tanyz)
=z2sec2yzy(yz)
=z2sec2yzz
=z3sec2yz
Now, find the expression for Sz.
Sz=z(z2tanyz)
Step 3
Simplifying further,
Sz=z(z2)tan(yz)+z(tan(yz))z2
=2ztan(yz)+z2sec2(yz)y
=2ztan(yz)+sec2(yz)yz2
Hence.
Not exactly what you’re looking for?
Ask My Question

Expert Community at Your Service

  • Live experts 24/7
  • Questions are typically answered in as fast as 30 minutes
  • Personalized clear answers
Learn more