Find the first partial derivatives of the following functions. s(y, z) = z^2 tan yz

Amari Flowers

Amari Flowers

Answered question

2021-03-09

Find the first partial derivatives of the following functions.
s(y,z)=z2tanyz

Answer & Explanation

pattererX

pattererX

Skilled2021-03-10Added 95 answers

Step 1
Consider the provided function,
S(y,z)=z2tanyz
Find the first partial derivatives.
So, we find the expression for SyandSz.
First we find the expression for Sy.
Sy=y(z2tanyz)
Step 2
Simplifying further,
Sy=y(z2tanyz)
=z2y(tanyz)
=z2sec2yzy(yz)
=z2sec2yzz
=z3sec2yz
Now, find the expression for Sz.
Sz=z(z2tanyz)
Step 3
Simplifying further,
Sz=z(z2)tan(yz)+z(tan(yz))z2
=2ztan(yz)+z2sec2(yz)y
=2ztan(yz)+sec2(yz)yz2
Hence.

Do you have a similar question?

Recalculate according to your conditions!

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?