Evaluate the integral int_-2^2(dp)/(sqrt(4-p^2))

generals336 2020-12-28 Answered
Evaluate the integral
22dp4p2
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Expert Answer

Dora
Answered 2020-12-29 Author has 98 answers
Step 1
Consider the provided improper integral,
22dp4p2
Evaluate the following integrals.
Apply the substitution method,
Letp=2sinudp=2cosudu.
p=2u=π2
p=2u=π2
Step 2
So, the integral becomes.
22dp4p2=π2π21du
=[1u]π2π21du
=[u]π2π21du
=π2+π2=π
Hence.
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