Evaluate the integral. int sin^-1x/(sqrt(1-x^2))

ringearV 2020-12-07 Answered
Evaluate the integral.
sin1x1x2
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Expert Answer

Faiza Fuller
Answered 2020-12-08 Author has 108 answers
Step 1
Consider the provided integral,
sin1x1x2dx
Evaluate the integrals.
Apply the Substitution method,
u=sin1xdu=11x2dx
Step 2
Therefore,
sin1x1x2dx=udu
=u1+11+1+C
=u22+C
Substitute back u=sin1x.
sin1x1x2dx=(sin1x)22+C
=12(sin1x)2+C
Hence.
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