Evaluate the integrals. int_-2^2(3x^4-2x+1)dx

Maiclubk 2021-02-09 Answered
Evaluate the integrals.
22(3x42x+1)dx
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Expert Answer

Alix Ortiz
Answered 2021-02-10 Author has 109 answers
Step 1:Given that
Evaluate integrals.
22(3x42x+1)dx
Step 2:Solving the integral
We have,
22(3x42x+1)dx=223x4dx222xdx+221dx
=3[x55]222[x22]22+[x]22
=35[25(2)5][22(2)2]+[2(2)]
=35(32(32))(44)+(2+2)
35(64)0+4
=1925+4
=192+205
=2125=42.4
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