# Evaluate the following definite integrals: int_0^1(x^4+7e^x-3)dx

Evaluate the following definite integrals:
${\int }_{0}^{1}\left({x}^{4}+7{e}^{x}-3\right)dx$
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Step 1
To Evaluate the following definite integrals:
Step 2
Given That
${\int }_{0}^{1}\left({x}^{4}+7{e}^{x}-3\right)dx$
$={\left[\frac{{x}^{5}}{5}+7{e}^{x}-3x\right]}_{0}^{1}\left[\begin{array}{c}\int {x}^{n}dx=\frac{{x}^{n}+1}{n+1}+c\\ \int {e}^{x}dx={e}^{x}+c\end{array}\right]$
$=\frac{1}{5}+7{e}^{1}-3\left(1\right)-0-7{e}^{0}+3\left(0\right)$
$=\frac{1}{5}+7e-3-7$
$=\frac{1}{5}+7e-10$
$=7e-\frac{49}{5}$
$\therefore {\int }_{0}^{1}\left({x}^{4}+7{e}^{x}-3\right)dx=7e-\frac{49}{5}$