Evaluate the following definite integrals: int_0^1(x e^(-x^2+2))dx

iohanetc 2021-02-19 Answered
Evaluate the following definite integrals:
01(xex2+2)dx
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Expert Answer

casincal
Answered 2021-02-20 Author has 82 answers
Step 1
To Evaluate the following definite integrals:
Step 2
Given That
01xex2+2dx
Let ex2+2=u
dudx=2x(ex2+2)
du2=xex2+2dx
Hence 01xex2+2dx=01du2
=12[4]01
Since we have u=ex2+2 Then we have
=12[ex2+2]01
=12[e1e2]
=12[ee2]=12[e2e]
01xex2+2dx=12(e2e)
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