first derivative of the given function

Answered question

2022-01-10

first derivative of the given function

y=cot5x

Answer & Explanation

nick1337

nick1337

Expert2022-02-08Added 777 answers

Find the derivative of the following via implicit differentiation:
ddx(y)=ddx(cot(5x))

Using the chain rule, ddx(y)=dy(u)dududx, where u=x and ddu(y(u))=y(u):
(ddx(x))y(x)=ddx(cot(5x))

The derivative of x is 1:
1y(x)=ddx(cot(5x))
INTERMEDIATE STEPS:
Possible derivation:
ddx(x)
The limit definition of the derivative for a function f(x) is ddx(f(x))=limh0f(x+h)f(x)h. Let f(x)=x. Then:
f(x+h)=(x+h)
Substitute f(x+h) and f(x) into the limit definition for the derivative:
ddx(x)=limh0(x+h)xh
Combine like terms in the numerator:
=limh0hh
The limit variable h approaches, but is never equal to, 0 and therefore can be algebraically canceled:
=limh01
The limit of any constant is that constant, so simplify to finish computing the derivative:
ddx(x)=1

Using the chain rule, ddx(cot(5x))=dcot(u)dududx, where u=5x and ddu(cot(u))=csc2(u):
y(x)=csc2(5x)(ddx(5x))
INTERMEDIATE STEPS:
Possible derivation:
ddx(cot

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