gorovogpg
2021-12-26
Answered

Solve the following differential Equation

You can still ask an expert for help

esfloravaou

Answered 2021-12-27
Author has **43** answers

\(\displaystyle{y}\text{}+{8}{y}\text{

Joseph Fair

Answered 2021-12-28
Author has **34** answers

Auxiliary Equation

Let

The solution is of the form

Result: we obtain real and equal roots with multiplicity 4

karton

Answered 2022-01-09
Author has **439** answers

asked 2022-02-18

Solve the following first-order nonlinear ordinary differential equation:

${y}^{\prime}\left(x\right)+\mathrm{log}\left(y\left(x\right)\right)=-x-1$

asked 2020-12-30

Solve differential equation$x{y}^{\prime}+3y=6{x}^{3}$

asked 2022-03-24

**Please find laplace and inverse Laplace**

asked 2022-03-16

What is the inverse laplace transform of $F\left(s\right)=\frac{1}{2}\mathrm{ln}\left(\frac{{s}^{{}^{\left\{2\right\}}}+{b}^{2}}{{s}^{{}^{\left\{2\right\}}}+{a}^{2}}\right)$ with $a,b\text{}\u03f5\text{}\mathbb{R}$ ?

asked 2021-02-05

Solve. $\frac{dy}{dx}+\frac{3}{x}y=27{y}^{\frac{1}{3}}1n\left(x\right),x>0$

asked 2022-05-15

Im clueless on how to solve the following question...

$x{e}^{y}\frac{dy}{dx}={e}^{y}+1$

What i've done is...

$\frac{dy}{dx}=\frac{1}{x}+\frac{1}{x{e}^{e}};\frac{dy}{dx}-\frac{1}{x{e}^{e}}=\frac{1}{x}$

Find the integrating factor..

$v(x)={e}^{P(x)};whereP(x)=\int p(x)dx\Rightarrow P(x)=\int \frac{1}{x}dx=ln|x|\phantom{\rule{0ex}{0ex}}v(x)={e}^{P(x)}={e}^{ln|x|}=x;\phantom{\rule{0ex}{0ex}}y=\frac{1}{v(x)}\int v(x)q(x)dx=\frac{1}{x}\int x\frac{1}{x}dx=1+c$

I know I made a mistake somewhere. Would someone advice me on this?

$x{e}^{y}\frac{dy}{dx}={e}^{y}+1$

What i've done is...

$\frac{dy}{dx}=\frac{1}{x}+\frac{1}{x{e}^{e}};\frac{dy}{dx}-\frac{1}{x{e}^{e}}=\frac{1}{x}$

Find the integrating factor..

$v(x)={e}^{P(x)};whereP(x)=\int p(x)dx\Rightarrow P(x)=\int \frac{1}{x}dx=ln|x|\phantom{\rule{0ex}{0ex}}v(x)={e}^{P(x)}={e}^{ln|x|}=x;\phantom{\rule{0ex}{0ex}}y=\frac{1}{v(x)}\int v(x)q(x)dx=\frac{1}{x}\int x\frac{1}{x}dx=1+c$

I know I made a mistake somewhere. Would someone advice me on this?

asked 2021-09-23

Use the accompanying tables of Laplace transforms and properties of Laplace transforms to find the Laplace tranform of the function below.

${e}^{-2t}\mathrm{cos}6t+{e}^{5t}-1$