To solve: x2−6x=x(8+x)

Question

Jimmy Macias · Accepted Answer

Calculation:  By distributive property,  x(8+x)=x⋅8+x⋅x  x(8+x)=8x+x2  Replace x(8+x) with 8x+x2  x2−6x=8x+x2  Add −x2−8x on both sides,  x2−6x−x2−8x=8x+x2−x2−8x  Add the like terms,  0x2−14x=0x2+0x  −14x=0  x=0  The value of x is 0.

Dabanka4v · Accepted Answer

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation:

x^{2} - 6 \cdot x - (x \cdot (8 + x)) = 0

((x^{2}) - 6 x) - x \cdot (x + 8) = 0

- 14 x = 0

Multiply both sides of the equation by (-1):

14 x = 0

Divide both sides of the equation by 14:

x = 0

karton · Accepted Answer

Use the distributive property to multiply x by 8+x
$x^{2} - 6 x = 8 x + x^{2}$
Subtract 8x from both sides.
$x^{2} - 6 x - 8 x = x^{2}$
Combine $- 6 x and - 8 x$ to get -14x.
$x^{2} - 14 x = x^{2}$
Subtract $x^{2}$ from both sides.
$x^{2} - 14 x - x^{2} = 0$
Combine $x^{2} and - x^{2}$ to get 0.
-14x=0
Product of two numbers is equal to 0 if at least one of them is 0. Since -14 is not equal to 0, x must be equal to 0.
x=0

To solve: x^{2}-6x=x(8+x)

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