To find total cost, to the nearest cent, to cool the house for this 24-hour period

CMIIh

CMIIh

Answered question

2020-12-30

To find total cost, to the nearest cent, to cool the house for this 24-hour period

Answer & Explanation

Alannej

Alannej

Skilled2020-12-31Added 104 answers

Given: 
The cost of maintaining the house adds up at a rate of $0.05.
Concept Used: 
Applications of integral 
Calculation: 
The rate at which the cost of maintaining the house rises
=0.055.23118.770(8010cos(π12)78) dt  
=0.055.23118.770(210cos(πt12)) dt  
=0.05[25.23118.770 dt 105.23118.770cos(πt12) dt ] 
=0.05[2(t)| (5.231)18.770120π(sin(πt12))|5.23118.770] 
putting the limits to get answer 
=0.055.23118.770(8010cos(π12)78) dt =5.096

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