Factor each of the algebraic expressions completely. 12x^{3}-52x^{2}-40x

osula9a 2021-12-26 Answered
Factor each of the algebraic expressions completely. 12x352x240x
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usumbiix
Answered 2021-12-27 Author has 33 answers
We find factor of 12x352x240x
We find factor of 12x352x240x
Now 12x352x240x
=x(12x252x40)
=4x(3x213x10)
=4x(3x215x+2x10)
=4x(3x(x5)+2(x5))
=4x(x5)(3x+2)
Hence 12x352x240x=4x(x5)(3x+2)
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Karen Robbins
Answered 2021-12-28 Author has 49 answers
12x352x240x
Factor 4x out of 12x352x240x
4x(3x213x10)
4x(3x+2)(x5)
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Vasquez
Answered 2022-01-08 Author has 460 answers

((12 * (x3))-(22 * 13x2))-40x
((22 * 3x2)-(22 * 13x2))-40x
12x3-52x2-40x=4x * (3x2-13x-10)
Factoring 3x2-13x-10
The first term is, 3x2 its coefficient is 3.
The middle term is, -13x its coefficient is -13.
The last term, "the constant", is -10
Step-1 : Multiply the coefficient of the first term by the constant 3 * -10 = -30
Step-2 : Find two factors of -30 whose sum equals the coefficient of the middle term, which is -13.
-30+1=-29
-15+2=-13
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -15 and 2.
3x2 - 15x + 2x - 10
Step-4 : Add up the first 2 terms, pulling out like factors :
3x * (x-5)
Add up the last 2 terms, pulling out common factors:
2 * (x-5)
Step-5 : Add up the four terms of step 4:
(3x+2) * (x-5)
Which is the desired factorization
Answer: 4x * (x-5) * (3x+2)

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