\frac{dy}{dx}=-\frac{ax+by}{bx+cy}

jamessinatraaa

jamessinatraaa

Answered question

2021-12-31

dydx=ax+bybx+cy

Answer & Explanation

Hector Roberts

Hector Roberts

Beginner2022-01-01Added 31 answers

Given exact differential equation is
dydx=ax+bybx+cy
The standard exact differential equation is represented as,
Mdx+Ndy=0
It should satisfy the condition of exactness
My=Nx
Lets
Robert Pina

Robert Pina

Beginner2022-01-02Added 42 answers

dydx=yy=axbybxcy, multiply equation with bxcy
(axby)+(bxcy)y=0
M(x,y)=axbyNy=b
N(x,y)=bxcyNx=b
Since MyNx given equation is not exact.
Vasquez

Vasquez

Expert2022-01-08Added 669 answers

dy/dx=(ax+by)/(bx+cy)+y=0
Then, (ax+bybx+cy)x0
in general, while (1)y=0.

Do you have a similar question?

Recalculate according to your conditions!

New Questions in Differential Equations

Ask your question.
Get an expert answer.

Let our experts help you. Answer in as fast as 15 minutes.

Didn't find what you were looking for?