\frac{dy}{dx}=-\frac{ax+by}{bx+cy}

jamessinatraaa 2021-12-31 Answered
dydx=ax+bybx+cy
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Expert Answer

Hector Roberts
Answered 2022-01-01 Author has 31 answers
Given exact differential equation is
dydx=ax+bybx+cy
The standard exact differential equation is represented as,
Mdx+Ndy=0
It should satisfy the condition of exactness
My=Nx
Lets

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Robert Pina
Answered 2022-01-02 Author has 42 answers
dydx=yy=axbybxcy, multiply equation with bxcy
(axby)+(bxcy)y=0
M(x,y)=axbyNy=b
N(x,y)=bxcyNx=b
Since MyNx given equation is not exact.

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Vasquez
Answered 2022-01-08 Author has 460 answers

dy/dx=(ax+by)/(bx+cy)+y=0
Then, (ax+bybx+cy)x0
in general, while (1)y=0.

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