It takes a person 50 minutes to get to campus. He spends t minutes walking to the bus stop and the rest of the time riding the bus. His walking rate is 0.06 miles per minute and the bus travels at a rate of 0.5 miles per minute. The total distance walking and traveling by bus is given by the algebraic expression 0.06t+0.5(50−1). (a) Simplify the algebraic expression (b) Use each form of the algebraic expression to determine the total distance that the person travels if the person spends 20 minutes walking to the bus stop. (a) The simplified expression is. (Do not factor.) (b) Using the given expression, it is found that the total distance that the person travels is miles if he spends 20 minutes walking to the bus stop. Using the simplified expression, it is found that the total distance that the person travels is miles if the person spends 20 minutes walking to the bus stop.

Question

It takes a person 50 minutes to get to campus. He spends t minutes walking to the bus stop and the rest of the time riding the bus. His walking rate is 0.06 miles per minute and the bus travels at a rate of 0.5 miles per minute. The total distance walking and traveling by bus is given by the algebraic expression 0.06t+0.5(50−1).   (a) Simplify the algebraic expression (b) Use each form of the algebraic expression to determine the total distance that the person travels if the person spends 20 minutes walking to the bus stop.   (a) The simplified expression is. (Do not factor.) (b) Using the given expression, it is found that the total distance that the person travels is miles if he spends 20 minutes walking to the bus stop. Using the simplified expression, it is found that the total distance that the person travels is miles if the person spends 20 minutes walking to the bus stop.

John Koga · Accepted Answer

Total time=50 minutes Walking time=t Riding time=50−t Walking rate=0.06 milesminute Bus speed=0.5 milesminute Part a) Simplifying the Algebraic Expression. 0.06t+0.5(50−t) =0.06t+25−0.5t =25−0.44t Part b) if the Person spends 20 minutes walking to the bus stop. Total distance travelled by him. =25−0.44t =25−0.44×20 =25−8.8 =16.2 miles

otoplilp1 · Accepted Answer

Answer: a) d(t)=25−0.44t b) d(t)=16.2 mles Step-by-step explanation: Question incomplete. From google, I found two question a) Simplify algebraic expression b) Use each form of the algebraic expression to determine the total distance that you travel if you spend 20 minutes walking to the bus stop Answer: a) d(t)=0,06t+0.5(50−t) d(t)=0,06t+25−0,5t d(t)=25−0.44t b) d(t)=25−0.44t for t=20 min d(t)=25−0.44⋅(20) d(t)=25−8.8 d(t)=16.2 miles

user_27qwe · Accepted Answer

Answer: a) S(t)=30-0.44t b) The person travels 21 miles Step-by-step explanation: (a) Simplify the algebraic expression: About the algebraic expression, the problem states that: The total distance walking and traveling by bus is given by the algebraic expression 0.06 t plus 0.5 left parenthesis 60 minus t right parenthesis. Mathematically, this is: S(t)=0.06t+0.5 * (60-t) Simplifying, we have: S(t)=0.06t+30-0.5t S(t)=30-0.44t b) Use each form of the algebraic expression to determine the total distance that the person travels if the person spends 20 minutes walking to the bus stop. t is the time that the person spends walking to the bus stop, so Pt=2. By the original expression S(t)=0.06t+0.5 * (60-t) S(20)=0.0620+0.5 * (60-20)=1.2=20=21.2 By the simplified expression S(t)=30-0.44t  S(20)=30-0.44 * (20)=30-8.8=21.2 By each form of the expression, we find that the person traveled 21.2 miles

It takes a person 50 minutes to get to campus. He spends t m

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