How many liters of a 25% alcohol solution and how

b2sonicxh

b2sonicxh

Answered question

2021-12-31

How many liters of a 25% alcohol solution and how many liters of a 12% alcohol solution must be mixed to create 13 liters of a 15% alcohol solution?

Answer & Explanation

Timothy Wolff

Timothy Wolff

Beginner2022-01-01Added 26 answers

Step 1
Let the number of liters of 25% alcohol solution and 12% alcohol solution required be x and y
According to question,
x+y=13 (1)
0.25x+0.12y=0.1513
25x+12y=195 (2)
Step 2
Multiply Eq.(1) with 12
12x+12y=156 (3)
Subtract Eq.(3) from (2)
13x=39
x=3
From Eq.(1)
x+y=13
3+y=13
y=10
To create 13 liters of a 15% alcohol solution we need 3 liters of 25% alcohol solution and 10 liters of 12% alcohol solution
Lakisha Archer

Lakisha Archer

Beginner2022-01-02Added 39 answers

25x+12(13x)=1513
25x+15612x=195
25x12x=195156
13x=3913
x= 3 liters 25.00% Alcohol 1
10 liters 12.00% Alcohol 2
karton

karton

Expert2022-01-04Added 613 answers

Solution A
Concentration = 25%=0.25
Amount =x
Solution B
Concentration = 12%=0.12
Amount = 13-x
Resultant Solution
Concentration = 15%=0.15
Amount = 13 liters
(Concentration of AAmount of A)+(Concentration of BAmount of B)=(Concentration of ResultantAmount of Resultant)
0.25x+0.12(13-x)=0.15 * 13
0.25x+1.56-0.12x=1.95
0.25x+1.56-0.12x=1.95
0.13x=1.95-1.56
0.13x=0.39
0.13x/13=0.39/13
x=3
Amount of solution A = x = 3 liters
Amount of solution B = 13-x = 13-3 = 10 liters
Answer
3 liters of a 25% alcohol solution must be mixed with 10 liters of 12% solution to get 13 liters of 15% solution.

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