# Find \sin(120)

Find $$\displaystyle{\sin{{\left({120}\right)}}}$$

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ambarakaq8
$$\displaystyle{\sin{{\left({120}\right)}}}={\sin{{\left({180}-{120}\right)}}}={\sin{{\left({60}\right)}}}={\frac{{\sqrt{{{3}}}}}{{{2}}}}$$
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ol3i4c5s4hr
$$\displaystyle{\sin{{\left({120}°\right)}}}={\frac{{\sqrt{{{3}}}}}{{{2}}}}$$
user_27qwe

$$\sin(120)=\cos(90-120)$$
$$=\cos(-30)$$
As $$\cos(-x)=\cos(x)$$
$$\cos(-30)=\cos(30)=\frac{\sqrt{3}}{2}$$